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Sholpan [36]
2 years ago
5

Suppose you have some wolves and some dogs. Dogs are named and wolves are not. If you call a dog it will run to you. A wolf woul

d not. So, if you take care of a dog, then (in our pretend situation) you can let it run free. A wolf has to be caged all the time. Any pair of animals can fight, so you need to separate them. On a plane with one line you can place two dogs (one dog in each of the regions): they will not fight as they will be separated by a line, and they will run free. How many dogs and how many wolves can you place on a plane with three lines in general position?
Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
8 0

Answer:

4dogs and no wolves

Step-by-step explanation:

when a dog is taken care of (Trained) it could be let to run free in a definite region.

On a plane with one line we can place two dogs (one dog in each of the regions) and they will not fight as they will be separated by a line, and they will run free.

If we place three lines in general, then we would have four regions where 4 dogs can run free as they are separated by a line so as not to fight.

But for Wolves from the question it is deduced that:  A wolf has to be caged all the time and no matter how well you train a wolve, it wont yield to instructions.

With these two, wolves wont be allowed on the plane at all.

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1/2 / 4

The formula = keep, change, flip

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Flip 4 to 1/4

That equals 1/2 × 1/4 = 1/16

Answer = 1/16

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yKpoI14uk [10]

Answer:

<u><em>$4.50 or $4.5</em></u>

Step-by-step explanation:

<em><u>well, this is easy</u></em>

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2 years ago
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By defining how exponents work, we conclude that 4^3 = 64, so the correct option is A.

<h3>How to find the cube of 4?</h3>

Let's remember how exponents work.

If we have a number a to the exponent n:

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It means that we need to multiply the number a by itself n times.

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