Answer:
This section of the book provides step-by-step solutions to exercises with circled exercise numbers. These solutions provide models that can help.
Step-by-step explanation:
Answer:
The fifth term of the sequence is 1875
Step-by-step explanation:
This is a geometric sequence since each consecutive term is being multiplied by 5. Therefore, the 5th term would be 5 times the 4th term, or 375*5=1875
A common denominator would be 24
Answer:
Yes, 3 is a primitive root of 7.
Step-by-step explanation:
By definition if primitive root, b is a primitive root of p, where p is a prime, if powers of b includes all residue classes mod p. Here,
mod 7=1
mod 7=3
mod 7=2
mod 7=6
mod 7=4
mod 7=5
And =numbers less than 7 and prime to 7=1,2,3,4,5,6, presents in the residue class of 3 mod 7, this proves 3 is a primitive root of 7.
Step-by-step explanation:
I am so sorry I just answered because I need points for my exam