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2 years ago

Label the net for the figure below with its dimensions.

Mathematics

2 answers:

kogti [31]2 years ago

6 0

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Below is the complete solution :
- two points on earth are :
(39N,120W) and (41N,84W)
midpoint between them = (39+41/2N, 120+84/2W)
= (802N, 104/2W)
= (40N,52W)

Ugo [173]2 years ago

4 0

Answer: 40N 52W

Step-by-step explanation: Hope this helps! :)

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Let f(x)=8/(1+3e)^(-0.7x)

Troyanec [42]

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8 8 8
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2 years ago

The path of a soccer ball is modeled by the function h(x) = -0.005x2 + 0.25x, where h is the height in meters and x is the horiz

NemiM [27]

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6 0

2 years ago

What is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27

malfutka [58]

Answer with explanation:

$\rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}$

→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

=(y+2)(y-5)

6 0

3 years ago

Read 2 more answers