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zhannawk [14.2K]
2 years ago
10

Given g(x) = 3 - x, what is the value of g(-9)?

Mathematics
1 answer:
Mandarinka [93]2 years ago
6 0

Answer:

-6

Step-by-step explanation:

g(x) = 3 - x

g(9) = 3 - 9

3-9 = -6

g(9) = -6

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Write an equation of the line that passes through the given point and is parallel to the given line.
9966 [12]

Answer : <em>Equation of line is</em> y=Equation of line is y=\frac{2}{3}x+\frac{-5}{3}

Step-by-step explanation:

Theory :

Equation of line is given as y = mx + c.

Where, m is slope and c is y intercepted.

Slope of given line : y = \frac{2}{3}x+1 is m= \frac{2}{3}

We know that line : y = \frac{2}{3}x+1 is parallel to equation of target line.

therefore, slope of target line will be \frac{2}{3}.

we write equation of target line as y= \frac{2}{3}x+c

Now, It is given that target line passes through point ( -5,-2)

hence, point ( -5,-2) satisfy the target line's equation.

we get,

y= \frac{2}{3}x+c

-2= \frac{2}{3} \times -5+ c

-5= \frac{-10}{3}+c

c= \frac{-5}{3}

thus, Equation of line is y=Equation of line is y=\frac{2}{3}x+\frac{-5}{3}

7 0
3 years ago
Three increased by the quotient of six and a number
GuDViN [60]

"Increased" means to add.

"Quotient" is a total of a division problem.

"A number" means the unknown.

This is our problem: 3 + 6 / N

8 0
3 years ago
Read 2 more answers
Consider the following function. f(x) = |x − 9| Find the derivative from the left at x = 9. If it does not exist, enter NONE. -1
nydimaria [60]

Answer with Step-by-step explanation:

We are given that

f(x)=\mid x-9\mid

f(x)=-(x-9) when x<9

f(x)=x-9 when x\geq 9

LHD

\lim_{x\rightarrow 9-}f'(x)

=-\lim_{x\rightarrow 9-}(x-9)=-1

RHD

\lim_{x\rightarrow 9+}f'(x)

=\lim_{x\rightarrow 9+}(x-9)=1

LHD\neq RHD

Hence, the function is not differentiable at x=9

8 0
3 years ago
Let k ( x ) = 2 x + 3 and m ( x ) = 3 x 2 + 7 x − 10 . Find the indicated value. M ( k ( − 4 ) ) =
murzikaleks [220]

Answer: 30

Step-by-step explanation:

Given

k(x)=2x+3

M(x)=3x^2+7x-10

M\left(k(x)\right) is given by replacing the x by k(x) from the M(x)

\Rightarrow M\left(k(x)\right)=3(2x+3)^2+7(2x+3)-10\\\Rightarrow M\left(k(x)\right)=3(4x^2+9+12x)+14x+21-10\\\Rightarrow M\left(k(x)\right)=12x^2+50x+38

Now, M\left(k(-4)\right) is

\Rightarrow M\left(k(-4)\right)=12(-4)^2+50(-4)+38\\\Rightarrow M\left(k(-4)\right)=192-200+38\\\Rightarrow M\left(k(-4)\right)=30

8 0
3 years ago
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