Answer:
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The goal of this function is to get a positive value under the square root sign so that the value would not be invalid. Evaluating F(3,1), the value is 1 + <span>sqrt(4-1^2) or equal to 1 + sqrt of 3.</span> In this case, the domain would be x equal to any numbers and the range equal to numbers from -2 ≤ y ≤ 2.
4a^4 -2b^2 +40
a=2
b=7
4(2)^4 -2(7)^2 +40
PEMDAS is what your gonna use to solve this you go from right to left
First is P which is parentheses which is none
second is E which stands for exponents
4(32)-2(49)+40
now MD multiply or divide
128-98+40
now add or subtract
30+40
last one
70 this is your answer i hope
All of them except for letter Z
f(x) = 6x - 12
y = 6x - 12
y + 12 = 6x - 12 + 12
<u>y + 12</u> = <u>6x</u>
6 6
¹/₆y + 2 = x
y = ¹/₆x + 2
f⁻¹(x) = ¹/₆x + 2
f⁻¹(-3) = ¹/₆(-3) + 2
f⁻¹(-3) = -¹/₂ + 2
f⁻¹(-3) = 1¹/₂
(x, f⁻¹(x)) = (-3, 1¹/₂)
