Force = mass * acceleration
Force = 0.3 km * 8m = 2.4 N
I got a different answer from a,b,c
Answer:
Range: (-3,0,3,6,9)
Step-by-step explanation:
We need to evaluate each value in the domain of the function, so
f(-2)=3(-2)+3=-6+3=-3
f(-1)=3(-1)+3=-3+3=0
f(0)=3(0)+3=0+3=3
f(1)=3(1)+3=3+3=6
f(2)=3(2)+3=6+3=9
The fraction of the variability in fuel economy is accounted for by the engine size is 59.91%.
Given that, r= -0.774.
To solve such problems we must know about the fraction of the variability in data values or R-squared.
<h3>What fraction of the variability in fuel economy is accounted for by the engine size?</h3>
The fraction by which the variance of the dependent variable is greater than the variance of the errors is known as R-squared.
It is called so because it is the square of the correlation between the dependent and independent variables, which is commonly denoted by “r” in a simple regression model.
Fraction of the variability in data values = (coefficient of correlation)²= r²
Now, the variability in fuel economy = r²= (-0.774)²
= 0.599076%= 59.91%
Hence, the fraction of the variability in fuel economy accounted for by the engine size is 59.91%.
To learn more about the fraction of the variability visit:
brainly.com/question/2516132.
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Answer:
Im pretty sure its 2
Step-by-step explanation:
sowwy if wrong
<span>y=3/7x + 18
Hope this helps
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