Well, you would use Punnet squares. Don't forget that heterozygous means that the alleles are different so Rr. Homozygous means that the genotype will have the same genes rr. When you put together the Punnet squares, I always like to determine the percentage of phenotypes possible. In this case 50% of them are going to be white, and 50% of them are going to be red.
Answer:
3
Explanation:
Heterozygous mice at both loci would be BbAa genotype.
B (black) is dominant over b (white) but the presence of A results in agouti.
Crossing two heterozygous:
BbAa x BbAa
Progeny
<em>9 B_A_ - Agouti</em>
<em>3 bbA_ - agouti</em>
<em>3 B_aa - Black</em>
<em>1 bbaa - white</em>
Hence, 3 out of 16 progeny will be black in color.
<em>See the attached image for the Punnet's square analysis of the cross.</em>
