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tiny-mole [99]
3 years ago
5

Campsite f and g are on opposite sides of the lake a survey crew made measurements on the diagram. What is the distance between

the 2 campsites

Mathematics
1 answer:
KatRina [158]3 years ago
3 0

Answer:

GF is 42.3 meters

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Verify if segment AB is parallel to segment FG

we know that

If segment AB is parallel to segment FG

then

Triangle ABO would be similar to Triangle GFO by AA Similarity theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional

so

\frac{AO}{GO}=\frac{BO}{FO}

substitute the given values

\frac{82}{73.8}=\frac{92}{82.8}

Multiply in cross

82(82.8)=92(73.8)\\6,789.6=6,789.6

Is true

Therefore

Corresponding sides are proportional

segment AB is parallel to segment FG

Triangle ABO is similar to Triangle GFO by AA Similarity theorem

Find the distance between the two campsites FG

Applying proportion

\frac{AO}{GO}=\frac{AB}{GF}

substitute

\frac{82}{73.8}=\frac{47}{GF}

solve for GF

GF=73.8(47)/82\\GF=42.3\ m

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If 5x−4y=22 and 3x+6y=30, what is the value of x−5y
amm1812

Answer:

-4 See Below:

Step-by-step explanation:

When you have a system of equations, you need to solve for one variable, and subsitute that variable into the other equation to solve for the other variables value.

3x +6y = 30 In this case, it would be easier to solve for x.

3x= 30-6y  Divide both sides by 3

x= 10-2y

Now we substitute for x in the other equation.

5x- 4y = 22

5(10-2y)-4y=22

50-10y-4y=22

50-14y=22 Add 14y to both sides

50= 14y + 22 Subtract 22 from both sides

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Substitute y=2 and solve for x.

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x= 10-2*2

x= 10-4

x= 6

Now we know y=2 and x=6, so we can substitute them into x-5y to find its value.

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= -4

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You have quarters and dimes that total $2.80. your friend says it is possible that the number of quarters is 8 more than the num
ss7ja [257]
To answer this question, you need to know that a quarter is worth $0.25 and dimes worth $0.10. In this case, the total number of money that made from quarters and dimes is $2.80
With Q=quarter and D=dime, then the equation should be:
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The condition that needs to be fulfilled in this case is that the quarter should be 8 more than dimes. Then you need to find out the highest possible number of the quarter and lowest possible number of the dimes.  
If you divide 2.8 with 0.25 you will found it will be 11.2 but 11 quarter will result with 0.05 value which you cannot remove, so the highest possible of the quarter should be 10.
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