Answer:
-4 See Below:
Step-by-step explanation:
When you have a system of equations, you need to solve for one variable, and subsitute that variable into the other equation to solve for the other variables value.
3x +6y = 30 In this case, it would be easier to solve for x.
3x= 30-6y Divide both sides by 3
x= 10-2y
Now we substitute for x in the other equation.
5x- 4y = 22
5(10-2y)-4y=22
50-10y-4y=22
50-14y=22 Add 14y to both sides
50= 14y + 22 Subtract 22 from both sides
28 = 14y Divide by 14 on both sides.
y = 2
Substitute y=2 and solve for x.
x = 10- 2y
x= 10-2*2
x= 10-4
x= 6
Now we know y=2 and x=6, so we can substitute them into x-5y to find its value.
x - 5y
= 6-5*2
=6-10
= -4
Answer:
Area= 648
Step-by-step explanation:
Area formula: L times W times H
9 times 6 times 12 :)
180-39-55=86°
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To answer this question, you need to know that a quarter is worth $0.25 and dimes worth $0.10. In this case, the total number of money that made from quarters and dimes is $2.80
With Q=quarter and D=dime, then the equation should be:
2.80= 0.25 Q + 0.10 D
The condition that needs to be fulfilled in this case is that the quarter should be 8 more than dimes. Then you need to find out the highest possible number of the quarter and lowest possible number of the dimes.
If you divide 2.8 with 0.25 you will found it will be 11.2 but 11 quarter will result with 0.05 value which you cannot remove, so the highest possible of the quarter should be 10.
If the highest possible of the quarter is 10, then the lowest possible of dimes should be:
2.8= 0.25(10) + 0.10D
0.10D= 0.3
D=3
Since 10-3 is 7, then it is not possible for the quarter to be 8 more than the dimes.