The equation of the piecewise function is 
<h3>The piecewise function</h3>
On the graph, we have:
- y = 3 for all x values not more than -1
- y = -1 for all values greater than 2
Hence, the piecewise function is:

<h3>The domain of the function</h3>
This is the set of input values
In (a), we have:
x ≤ -1 and x > 2
Hence, the domain is (∞, 3] u (2, ∞)
<h3>The range of the function</h3>
This is the set of output values
In (a), we have:
f(x) = 3 and f(x) -1
Hence, the range is [3] u (-1)
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Answer:
The answer is D
Step-by-step explanation:
I did it on edg
The area of the surface is given exactly by the integral,

We have

so the area is

We split up the domain of integration into 10 subintervals,
[0, 1/2], [1/2, 1], [1, 3/2], ..., [4, 9/2], [9/2, 5]
where the left and right endpoints for the
-th subinterval are, respectively,


with midpoint

with
.
Over each subinterval, we interpolate
with the quadratic polynomial,

Then

It turns out that the latter integral reduces significantly to

which is about 651.918, so that the area is approximately
.
Compare this to actual value of the integral, which is closer to 1967.
Answer/Step-by-step explanation:
Slope (m) = rise/run
y-intercept (b) = starting value or the point on the y-axis where the line cuts across
✔️Slope (m) of skater 1:
Rise = 45
Run = 7.5
Slope (m) = 45/7.5 = 6
✔️ y-intercept (b) of Skater 1:
b = 0 (the y-axis is intercepted at 0)
✔️Skater 1 linear function in slope-intercept form, y = mx + b
Substitute m = 6 and b = 0 into y = mx + b
Linear function: y = 6x + 0
y = 6x
✔️Slope (m) of skater 2:
Rise = 30
Run = 15
Slope (m) = 30/15 = 2
✔️ y-intercept (b) of Skater 2:
b = 0 (the y-axis is intercepted at 0)
✔️Skater 2 linear function in slope-intercept form, y = mx + b
Substitute m = 2 and b = 0 into y = mx + b
Linear function: y = 2x + 0
y = 2x