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3 years ago

the length of a rectangle is 5 inches more than the width the area is 33 square inches find the length and width

Mathematics

1 answer:

TEA [102]3 years ago

5 0

Try to draw a rectangle and follow those instructions and do u know length times width

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10 times The sum of half a numberand six is eight

GuDViN [60]

The numerical form of this worded expression is:

10(1/2n + 6)=8

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3 years ago

You are riding a roller coaster when a shoe falls off your foot. The function y=300−16t2 represents the height y (in feet) of th

Juli2301 [7.4K]

Answer:

Time to land on 11ft is 4.25 seconds

Step-by-step explanation:

Given

$y = 300 - 16t^2$

Required

Solve for t when height is 11ft

This implies that $y = 11$

So: substitute 11 for y in $y = 300 - 16t^2$

$11 = 300 - 16t^2$

Collect Like Terms

$16t^2 = 300 - 11$

$16t^2 = 289$

Express both sides as squares

$4^2 * t^2 = 17^2$

$(4t)^2 = 17^2$

Take square roots of both sides (ignore negative)

$4t = 17$

Solve for t

$t = \frac{17}{4}$

$t = 4.25$

Hence, time to land on 11ft is 4.25 seconds

8 0

2 years ago

Which region labeled in the graph below would represent the solution (the final shaded area) to the system of linear inequalitie

Elena L [17]

Answer:

Region D.

Step-by-step explanation:

Here we have two inequalities:

y ≤ 1/2x − 3

y < −2/3x + 1

First, we can see that the first inequality has a positive slope and the symbol (≤) so the values of the line itself are solutions, this line is the solid line in the graph.

And we have that:

y ≤ 1/2x − 3

y must be smaller or equal than the solid line, so here we look at the regions below the solid line, which are region D and region C.

Now let's look at the other one:

y < −2/3x + 1

y = (-2/3)*x + 1

is the dashed line in the graph.

And we have:

y < −2/3x + 1

So y is smaller than the values of the line, so we need to look at the region that is below de dashed line.

The regions below the dashed line are region A and region D.

The solution for the system:

y ≤ 1/2x − 3

y < −2/3x + 1

Is the region that is a solution for both inequalities, we can see that the only region that is a solution for both of them is region D.

Then the correct option is region D.

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3 years ago

Find the value of X (multiple choice)

sdas [7]

Answer:

Step-by-step explanation:

trust meee

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3 years ago

Think about the SSS Congruence Postulate. Why do you think it is a postulate and not a theorem?

Softa [21]

I don't know I am sorry I could not help U

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3 years ago