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Elan Coil [88]
2 years ago
14

2x2-3x-2=x+4 select all the solutions

Mathematics
1 answer:
Papessa [141]2 years ago
5 0
Solve for x over the real numbers:2 x^2 - 3 x - 2 = x + 4
Subtract x + 4 from both sides:2 x^2 - 4 x - 6 = 0
The left hand side factors into a product with three terms:2 (x - 3) (x + 1) = 0
Divide both sides by 2:(x - 3) (x + 1) = 0
Split into two equations:x - 3 = 0 or x + 1 = 0
Add 3 to both sides:x = 3 or x + 1 = 0
Subtract 1 from both sides:Answer:  x = 3 or x = -1
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I need help on math.<br>h(x)=8x-10<br>h( )=62
andriy [413]

Simplifying

8x + -10 = 62


Reorder the terms:

-10 + 8x = 62


Solving

-10 + 8x = 62


Solving for variable 'x'.


Move all terms containing x to the left, all other terms to the right.


Add '10' to each side of the equation.

-10 + 10 + 8x = 62 + 10


Combine like terms: -10 + 10 = 0

0 + 8x = 62 + 10

8x = 62 + 10


Combine like terms: 62 + 10 = 72

8x = 72


Divide each side by '8'.

x = 9


Simplifying

x = 9

3 0
3 years ago
The product of 2x-3 and x+4 can be expressed as
erik [133]
6 is ur answer, good luck!
7 0
3 years ago
The ratio of students who prefer comedic plays to students who prefer romantic plays in the drama club is 2 to 3. If all student
masha68 [24]

Answer:

A

Step-by-step explanation:

2 to 3 means that the ratio of romantic students has a numerator of 3. If there is a numerator of 3 the denominator has to be 5 because 2+3 is five if the fraction is 3/5, then the answer is A.

4 0
3 years ago
The container that holds the water for the football team is 1/3 full. After pouring out 6 gallons of water it is 1/9 full. How m
andriy [413]
18 gallons I am
pretty sure
5 0
2 years ago
Read 2 more answers
what is the smallest of 3 consecutive positive integers if the product of smaller two interfere is 5 less than 5 times the large
Lady_Fox [76]

Answer:

Two options:

5,6, and 7

-1,0,and 1

Step-by-step explanation:

Three consecutive natural numbers can be represented as n, n+1, and n+2.

The product of the smaller two would be n(n+1). The less than 5 times the larger is 5(n+2)-5.

Set them equal and solve by factoring:

n(n+1) = 5(n+2) -5\\n^2+n = 5n+10 -5\\n^2+n = 5n+5\\n^2 -4n-5=0\\(n-5)(n+1)=0

Set each factor equal to 0.

n-5==0 so n=5.

n+1=0 so n=-1.

This means the 3 consecutive numbers would be 5,6, and 7

OR

-1, 0 or 1.

8 0
3 years ago
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