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Alborosie
3 years ago
9

Help me with the question A and B please urgent...

Mathematics
2 answers:
ankoles [38]3 years ago
8 0
The perimeter of an object is all of its sides added up. So it gives you the length and widths of the shape.
A. X + 4 + X + X + 4 + X = 34. But we can simply that even further. To 4X + 8 = 34

B. So solve that you would first Subtract 8 from each side. You then get 4x = 26
X = 13/2
13/2 is your answer. You can simplify this to 7.5 but ask your teacher if you can leave it as 13/2 because it will save you a lot of time on a test.
vampirchik [111]3 years ago
7 0
A: 34-8 = 26/4 = 6.5 so x=6.5
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34kurt
The answer is C

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42.5% of what is 20.57
babunello [35]
42.5% of what = 20.57

<span>42.5% of x = 20.57
</span>
(42.5/100)*x = 20.57

42.5x / 100 = 20.57

x = 20.57 * 100 / 42.5

x = 48.4

Therefore 42.5% of 48.4 is 20.57. 
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A construction crew needs to close 75% of a 5-mile road while they do construction. How much of the road is closed,
gulaghasi [49]

Answer:

6

Step-by-step explanation:

I did .75 x 5 to get 75% of the road. I then converted the amount into kilometers using a reliable converter. I got 6 kilometers then.

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Kevin and randy my use have a jar containing 64 coins all of which are either quarters or nickels. The total value of the coins
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3 years ago
The 20 to 34 age groups are approximately normally distributed with µ = 110
Savatey [412]

Answer:

21.94% of people aged 20 to 34 have IQs between 125 and 150.

Step-by-step explanation:

<u>The complete question is:</u> Scores on the Wechsler Adult Intelligence Scale (a standard IQ test) for the 20 to 34 age group are approximately Normally distributed with  μ = 110  and  σ = 25.

What percent of people aged 20 to 34 have IQs between 125 and 150?

Let X = <u><em>Scores on the standard IQ test for the 20 to 34 age group</em></u>

SO, X ~ Normal(\mu=110,\sigma^{2} =25^{2})

The z-score probability distribution for the normal distribution is given by;

                            Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 110

            \sigma = standard deviation = 25

Now, the percent of people aged 20 to 34 have IQs between 125 and 150 is given by = P(125 < X < 150) = P(X < 150) - P(X \leq 125)

       P(X < 150) = P( \frac{X-\mu}{\sigma} < \frac{150-110}{25} ) = P(Z < 1.60) = 0.9452

       P(X \leq 125) = P( \frac{X-\mu}{\sigma} \leq \frac{125-110}{25} ) = P(Z \leq 0.60) = 0.7258

The above probability is calculated by looking at the value of x = 1.60 and x = 0.60 which has an area of 0.9452 and 0.7258.

Therefore, P(125 < X < 150) = 0.9452 - 0.7258 = 0.2194 or 21.94%

7 0
4 years ago
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