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Softa [21]
4 years ago
15

Estimate how many minutes Jessica must practice basketball free throws if she has to shoot a total of 50 successful free throws,

and he
average is 3 successful free throws a minute.
A.3
B.17
C.47
D.53
E.150
Mathematics
2 answers:
Harman [31]4 years ago
7 0

Answer:

17

Step-by-step explanation:

average per minute is 3, and you need 50, so 3x?=50

to know "?" we change how the question is, so it ends 50/3=?

50/3= 16.6666666667 and the closest is 17

kirill115 [55]4 years ago
3 0
B.17 is the answer

Explanation:
50 divided by 3 = 16.6666667 rounded is 17
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12−(3x+13)=0<br> Someone plz tell me i will mark brainliest
Amanda [17]

Answer:

Step-by-step explanation:

The starting equation is

12-(3x+13)=0

First add 3x+13 to both sides so that only 12 is on the left

12=3x+13

now subtract 13 from both sides to isolate your variable

-1=3x

Finally divide both sides by 3 to get your final answer

x=-1/3

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3 years ago
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A study was recently conducted to estimate the mean cholesterol for adult males over the age of 55 years. From a random sample o
Komok [63]

Answer:  Correct critical value = 2.2622

Step-by-step explanation:

Confidence interval for population mean when population standard deviation is unknown:

\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}} , where \overline{x} = sample mean, n= sample size, s= sample standard deviation, t_{\alpha/2} = two-tailed t value.

As per given: n= 10

degree of freedom : df = n-1=9

\overline{x}=242.6\\\\s=73.33\\\\\alpha=5\%=0.05

Critical t-value : t_{\alpha/2,df}=t_{0.05/2,9}=t_{0.025,9}=2.2622

So, the 95 percent confidence interval estimate for the​ mean :

242.6\pm (2.2622)\dfrac{73.33}{\sqrt{10}}\\\\=242.6\pm (2.2622)(23.19)\\\\\approx242.6\pm52.46\\\\=(242.6-52.46,\ 242.6+52.46)\\\\=(190.14,\ 295.06)

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8 0
3 years ago
What is the inverse of the function f(x) = 2x - 10?
love history [14]
F(x)=2x-10

y=2x-10

x=2y-10

x+10=2y-10+10 (add both sides by 10)

2y=x+10

2y/2=x+10/2 (divide both sides by 2)

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3 years ago
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Lena [83]
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4 0
3 years ago
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PIT_PIT [208]
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