Question

You order fifteen burritos to go from a Mexican restaurant, five with hot peppers and ten without. However, the restaurant forgot to label them. If you pick three burritos at random, find the probability of the given event. (Round your answer to three decimal places.)
Exactly one has hot peppers.

Answer 1

Answer: 0.444

Step-by-step explanation:

Given : Total burritos ordered = 15

Number of burritos with hot peppers =5

Number of burritos without hot peppers=10

Then the probability that the burrito has hot peppers:-

$\dfrac{5}{15}=\dfrac{1}{3}$

Using binomial probability formula:-

$P(X)=^nC_xp^x(1-p)^{n-x}$

If you pick three burritos at random , then the probability of getting having exactly one burrito with hot peppers:-

$P(1)=^3C_1(\dfrac{1}{3})^1(\dfrac{2}{3})^{2}\\\\=(3)\dfrac{1}{3})^1(\dfrac{2}{3})^{2}=0.444444444444\approx 0.444$

Hence, the required probability = 0.444