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vagabundo [1.1K]
3 years ago
5

What is (1-i)^3 Please explain how you got that

Mathematics
1 answer:
My name is Ann [436]3 years ago
6 0

\bf (1-i)^3\implies ~\hfill \begin{array}{cccccccl} 1^3&+&3(1)^2(-i)^1&+&3(1)^1(i)^2&+&(-i)^3\\\\ 1&+&(-3i)&+&(3i^2)&+&(-i^3)\\\\ 1&-&3i&+&3i^2&-&i^3 \end{array} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{let's recall that}}{i^2=-1\qquad \qquad i^3=-i} \\\\[-0.35em] ~\dotfill\\\\ 1-3i+3(-1)-(-i)\implies 1-3i-3+i\implies -2-2i

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Patrice goes to fishers candy shop with the price of gummy candies modeled by the equation y=5/2x where x is the amount of gummy
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Answer:

You need to put the question, but I'll try to help as much as I can without the question. y=5/2x, if you put the amount of gummy candy in lbs in the x's place, and you multiply the amount by 5/2, you will get the price.

Step-by-step explanation:

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Eduardwww [97]

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MrRissso [65]

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4 0
3 years ago
URGENT MATH HELP BRAINLIEST
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Answer:

Step-by-step explanation:

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\frac{a}{Sin \ A}=\frac{b}{Sin \ B}=\frac{b}{Sin \ C}

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\frac{17}{Sin \ 90 \textdegree}=\frac{10}{Sin \ m\angle B}\\\\m\angle B=Sin^{-1}\frac{10}{(17/Sin \ 90\textdegree)}\\\\=36.03\textdegree

Hence  the angle B is 36.03°

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