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vagabundo [1.1K]
3 years ago
5

What is (1-i)^3 Please explain how you got that

Mathematics
1 answer:
My name is Ann [436]3 years ago
6 0

\bf (1-i)^3\implies ~\hfill \begin{array}{cccccccl} 1^3&+&3(1)^2(-i)^1&+&3(1)^1(i)^2&+&(-i)^3\\\\ 1&+&(-3i)&+&(3i^2)&+&(-i^3)\\\\ 1&-&3i&+&3i^2&-&i^3 \end{array} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{let's recall that}}{i^2=-1\qquad \qquad i^3=-i} \\\\[-0.35em] ~\dotfill\\\\ 1-3i+3(-1)-(-i)\implies 1-3i-3+i\implies -2-2i

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Which expression is equivalent to 0?<br> (a)(-a)<br> a +(-a)<br> a/-a <br> a - (-a)
cupoosta [38]

Answer:

a - a or (a +(-a))

Step-by-step explanation:

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6 0
3 years ago
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mixer [17]
Based on my knowledge, you’d set both equations equal to y, and then set both sides equal to each other then solve.

y=-5+x
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then solve from there

(this could be completely wrong, so don’t only go by my opinion)
3 0
3 years ago
I’m sure this is easy but i'm gonna ask anyway
Arada [10]
No, it's always okay to ask if you don't understand a question.  Anyway, for this problem, we just have to plug in the value for <em>V </em>to solve for <em>P</em> :

P = 4V^{ \frac{1}{3}} \\ P = 4(125)^{ \frac{1}{3}}

A number to the power of 1/3 is the same as taking a cube root.

P = 4(125)^{ \frac{1}{3}} \\ P = 4(5) \\ P=20

The perimeter of one face of the cube is 20m.
5 0
3 years ago
Ok this is stressin me out anyone know this
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Y=-9
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2 years ago
What is 12.87+3.905? Show how to solve please.
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