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OLga [1]
3 years ago
8

Write the equation in point slope form

Mathematics
2 answers:
solong [7]3 years ago
5 0
The equation in point slope form is
y-4 = (1/2)(x -2).

The equation for point slope form is
y - y1 = m(x - x1)

The point on the graph is given as (2,4) so you can substitute that into the equation as

y - 4 = m(x - 2)

M represents the slope.

By looking at the graph, you can see that the y-intercept is (0,3). The slope is change in y / change in x or the rise/run. From (0,3) to (2,4).

Change in y = 4 - 3 = 1
Change in x = 2 - 0 = 2

Therefore the slope = 1/2 = m.

Substitute m in for the slope and the final equation in point slope form would be y-4 = (1/2)(x -2).
Mars2501 [29]3 years ago
3 0

Answer: X=4/2x+3

Step-by-step explanation:

I just know

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Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4
gtnhenbr [62]

Answer:

Simplifying the expression (6^{-2})(3^{-3})(3*6)^4 we get \mathbf{108}

Step-by-step explanation:

We need to simplify the expression (6^{-2})(3^{-3})(3*6)^4

Solving:

(6^{-2})(3^{-3})(3*6)^4

Applying exponent rule: a^{-m}=\frac{1}{a^m}

=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\

Factors of 18=2\times 3\times 3=2\times3^2

Factors of 6=2\times 3

Replacing terms with factors

=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\

Using exponent rule: (a^m)^n=a^{m\times n}

=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}

Using exponent rule: a^m.a^n=a^{m+n}

=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}

Now using exponent rule: \frac{a^m}{a^n}=a^{m-n}

=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108

So, simplifying the expression (6^{-2})(3^{-3})(3*6)^4 we get \mathbf{108}

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Hi!

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