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Delicious77 [7]
3 years ago
10

Use the remainder theorem to verify this statement. (x+5) is a factor of the function f(x)= x^3+3x^2-25x-75. Find the (blank) of

f(x) and x+5. The (blank) of this operation is 0. Therefore, (x+5) is (blank) of function f. So f(blank) =0.
Blank choices:
1. product, sum, difference, or quotient
2. sum, discriminant, quotient, or remainder
3. the opposite, the simplified form, not a factor, a factor
4. -5, -75, 75, 5
Mathematics
1 answer:
Yuki888 [10]3 years ago
8 0

Answer:

Step-by-step explanation:

5 is a factor

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Please help thank you
Contact [7]

Answer:

TRUE

Step-by-step explanation:

4 0
2 years ago
Slope of a line that passes through the points (-4,-7) and (-2,-19) in simplest form
frozen [14]

Answer:

m=-6

Step-by-step explanation:

use slope formula to solve

m= rise/run=y2-y1/x2-x1

8 0
2 years ago
Write an equation that represents the following problem.
pogonyaev
35 + 0.05m = 50 + 0.01m <== ur equation
0.05m - 0.01m = 50 - 35
0.04m = 15
m = 15/0.04
m = 375.....u need to send 375 text messages for the plans to be equal
5 0
4 years ago
About 19​% of the population of a large country is hopelessly romantic. If two people are randomly​ selected, what is the probab
Aleksandr-060686 [28]

Answer:

3.61% probability that both are hopelessly romantic​.

34.39% probability at least one is hopelessly romantic

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are hopelessly romantic, or they are not. The probability of a person being hopelessly romantic is independent from other people. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

19​% of the population of a large country is hopelessly romantic.

This means that p = 0.19

Two people are randomly​ selected

This means that n = 2

What is the probability both are hopelessly romantic​?

This is P(X = 2). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.19)^{2}.(0.81)^{0} = 0.0361

3.61% probability that both are hopelessly romantic​.

What is the probability at least one is hopelessly romantic​?

P(X \geq 1) = P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{2,1}.(0.19)^{1}.(0.81)^{1} = 0.3078

P(X = 2) = C_{2,2}.(0.19)^{2}.(0.81)^{0} = 0.0361

P(X \geq 1) = P(X = 1) + P(X = 2) = 0.3078 + 0.0361 = 0.3439

34.39% probability at least one is hopelessly romantic

7 0
3 years ago
Write a proportion using an unknown value x and the ratio 5:6. Then solve it.
sesenic [268]
5/6 = x/12 
6 × 2 equals 12
So use 2 and multiple it by 5 and you get 10
so the proportion would be 
5/6 = x/12 6 × 2 = 12 5 × 2 = 10 = 10/12x
4 0
3 years ago
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