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scoundrel [369]
3 years ago
5

In two or more compete sentences, describe and solve a real world situation that can be modeled by the equation x - 225 = 550.

Mathematics
1 answer:
Basile [38]3 years ago
7 0

Step 1: Add 225 to both sides.<span><span><span>x−225</span>+225</span>=<span>550+225</span></span><span>x=775</span>Answer:<span>x=<span>775

If this is what your asking for, I got confused.

</span></span>
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PLEASE HELP I SUCK AT MATH
Lerok [7]

its B  y=4x

because all the number equals four like

2*4=8

3*4=12

4*4=16

5*4=20

4 0
3 years ago
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It’s either D or E; please help
sertanlavr [38]

Answer:

They should be blocked by body fat composition so the subjects are as similar as possible.

Step-by-step explanation:

It's D .

Blocking here means how should the subjects be arranged in terms of body fat or weight.

Option A is wrong because alphabetically controlling body fat would not get desired results.

Option B is wrong because different age groups would yield different results.

Option C is wrong also because weight loss is not dependent on taller people.

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8 0
3 years ago
Please help. Round 7,165.482 to the nearest hundredth.
FrozenT [24]
I believe the answer is C.
7 0
4 years ago
Read 2 more answers
(7p^(2)+3p)-(5p^(2)+4)<br> solve for standard form and show how you got it
inna [77]

\huge \boxed{\mathfrak{Question} \downarrow}

  • ( 7 p ^ { 2 } + 3 p ) - ( 5 p ^ { 2 } + 4 ). Solve for standard form.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

( 7 p ^ { 2 } + 3 p ) - ( 5 p ^ { 2 } + 4 )

To find the opposite of 5p²+4, find the opposite of each term inside the bracket.

7p^{2}+3p-5p^{2}-4

Combine 7p² and -5p² to get 2p².

\boxed{ \boxed{ \bf \: 2p^{2}+3p-4 }}

5 0
3 years ago
Please help and show step by step pls
Brut [27]

First notice that

<em>x</em> ² + 5<em>x</em> + 6 = (<em>x</em> + 3) (<em>x</em> + 2)

so you can rewrite everything with a common denominator:

5 / (<em>x</em> ² + 5<em>x</em> + 6) + 7 / (<em>x</em> + 2) = 6 / (<em>x</em> + 3)

5 / (<em>x</em> ² + 5<em>x</em> + 6) + 7 (<em>x</em> + 3) / ((<em>x</em> + 2) (<em>x</em> + 3)) = 6 (<em>x</em> + 2) / ((<em>x</em> + 3) (<em>x</em> + 2))

5 / (<em>x</em> ² + 5<em>x</em> + 6) + 7 (<em>x</em> + 3) / (<em>x</em> ² + 5<em>x</em> + 6) = 6 (<em>x</em> + 2) / (<em>x</em> ² + 5<em>x</em> + 6)

(5 + 7 (<em>x</em> + 3)) / (<em>x</em> ² + 5<em>x</em> + 6) = 6 (<em>x</em> + 2) / (<em>x</em> ² + 5<em>x</em> + 6)

As long as <em>x</em> ≠ -3 or <em>x</em> ≠ -2, the denominators are never zero, so we can cancel them and be left with

5 + 7 (<em>x</em> + 3) = 6 (<em>x</em> + 2)

Solving for <em>x</em> is easy from here:

5 + 7<em>x</em> + 21 = 6<em>x</em> + 12

7<em>x</em> - 6<em>x</em> = 12 - 5 - 21

<em>x</em> = -14

3 0
3 years ago
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