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sukhopar [10]
2 years ago
8

Please help and show step by step pls

Mathematics
1 answer:
Brut [27]2 years ago
3 0

First notice that

<em>x</em> ² + 5<em>x</em> + 6 = (<em>x</em> + 3) (<em>x</em> + 2)

so you can rewrite everything with a common denominator:

5 / (<em>x</em> ² + 5<em>x</em> + 6) + 7 / (<em>x</em> + 2) = 6 / (<em>x</em> + 3)

5 / (<em>x</em> ² + 5<em>x</em> + 6) + 7 (<em>x</em> + 3) / ((<em>x</em> + 2) (<em>x</em> + 3)) = 6 (<em>x</em> + 2) / ((<em>x</em> + 3) (<em>x</em> + 2))

5 / (<em>x</em> ² + 5<em>x</em> + 6) + 7 (<em>x</em> + 3) / (<em>x</em> ² + 5<em>x</em> + 6) = 6 (<em>x</em> + 2) / (<em>x</em> ² + 5<em>x</em> + 6)

(5 + 7 (<em>x</em> + 3)) / (<em>x</em> ² + 5<em>x</em> + 6) = 6 (<em>x</em> + 2) / (<em>x</em> ² + 5<em>x</em> + 6)

As long as <em>x</em> ≠ -3 or <em>x</em> ≠ -2, the denominators are never zero, so we can cancel them and be left with

5 + 7 (<em>x</em> + 3) = 6 (<em>x</em> + 2)

Solving for <em>x</em> is easy from here:

5 + 7<em>x</em> + 21 = 6<em>x</em> + 12

7<em>x</em> - 6<em>x</em> = 12 - 5 - 21

<em>x</em> = -14

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