The answer is 6.5t2+0.5t−5.5 , it’s simplified
Answer:
b
Step-by-step explanation:
Answer:
2100
Step-by-step explanation:
There are 21 consonants that can serve as the first and last letters. There are 5 vowels that can serve as the 2nd and 4th letters. There are 20 remaining consonants that can serve as the 3rd letter. (The same consonant cannot appear in all three places.)
So, the total number of 5-letter palindromes that start with a consonant and alternate with a vowel will be ...
21×5×20 = 2100 . . . different palindromes
As there are no parenthesis, Follow PEMDAS and go from left to right
14 x 13 = 182
182/9 = 20.22
20.22 + 8 = 28.22
28.22 is your answer
hope this helps
5(u+w) it is using distributive property.
