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3 years ago

A driver drives for 5.3 hours at an average speed of 50 MPH. What distance does she travel in this time?

Mathematics

1 answer:

Zinaida [17]3 years ago

4 0

Answer:265 meters

Step-by-step explanation:

time= 5.3 hr

Speed=50 m/h

The formula to find distance is:

Speed= distance / time

So make distance subject of th formula

distance= speed × time

distance= 50 m/hr × 5.3 hr

distance= 265 meters

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Find the probability of rolling divisors of 24

Monica [59]

Answer:

5/6 is the probability

Step-by-step explanation:

Factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24 and rolling a 6-sided die you can get 1, 2, 3, 4, 5, 6 so 5 is the only thing you can roll that isn't a factor of 24 so

4 0

2 years ago

PLease answer !!! Find constants $A$ and $B$ such that \[\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}\] for all

Xelga [282]

Answer:

1. $(A,B) = (3,-2)$

2. The values of t are: -3, -1

Step-by-step explanation:

Given

$\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}$

$|t| = 2t + 3$

Required

Solve for the unknown

Solving $\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}$

Take LCM

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{(x - 2)(x-1)}$

Expand the denominator

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{x^2 - 2x + x -2}$

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{x^2 - x -2}$

Both denominators are equal; So, they can cancel out

$x + 7 = A(x+1) + B(x-2)$

Expand the expression on the right hand side

$x + 7 = Ax + A + Bx - 2B$

Collect and Group Like Terms

$x + 7 = (Ax + Bx) + (A - 2B)$

$x + 7 = (A + B)x + (A - 2B)$

By Direct comparison of the left hand side with the right hand side

$(A + B)x = x$

$A - 2B = 7$

Divide both sides by x in $(A + B)x = x$

$A + B = 1$

Make A the subject of formula

$A = 1 - B$

Substitute 1 - B for A in $A - 2B = 7$

$1 - B - 2B = 7$

$1 - 3B = 7$

Subtract 1 from both sides

$1 - 1 - 3B = 7 - 1$

$-3B = 6$

Divide both sides by -3

$B = -2$

Substitute -2 for B in $A = 1 - B$

$A = 1 - (-2)$

$A = 1 + 2$

$A = 3$

Hence;

$(A,B) = (3,-2)$

Solving $|t| = 2t + 3$

Because we're dealing with an absolute function; the possible expressions that can be derived from the above expression are;

$t = 2t + 3$ and $-t = 2t + 3$

Solving $t = 2t + 3$

Make t the subject of formula

$t - 2t = 3$

$-t = 3$

Multiply both sides by -1

$t = -3$

Solving $-t = 2t + 3$

Make t the subject of formula

$-t - 2t = 3$

$-3t = 3$

Divide both sides by -3

$t = -1$

<em>Hence, the values of t are: -3, -1</em>

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2 years ago

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Write an addition expression and a subtraction expression, each with a value of 2.4 X 10 the power of negative 3.

Zolol [24]

Okay so first figure out what 2.4 times 10 with the power of negative 3 is.

2.4 times 10 is 24 and 24 to the power of 3 is 13,824

so an addition problem could be 5,986+7,838= 13,824

then you could do for a subtraction problem 23,789- 9,965 = 13,824

I hope this helped you. (;

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3 years ago

Help- ;-; i am struggling ;-; I- cant do this--

Tems11 [23]

Answer:

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3 years ago

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Korolek [52]

Answer:

I don't know sooooooooop

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2 years ago

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