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kotegsom [21]
2 years ago
10

How many liters of a 25 percent saline solution must be added to 3 liters of a 10 percent saline solution to obtain a 15 percent

saline solution?
Mathematics
1 answer:
baherus [9]2 years ago
7 0
Assume we need to add x litters.

So we are going to mix x liters (25% saline) and and 3 liters (10% saline).

In total we are going to have a x+3 litters (of 15% saline).



a. of the x liters, 25/100x=0.25x is saline. so we have 0.25x liters saline.

b. of the 3 liters, (10/100)*3=0.1*3=0.3 liters is saline.


c. of the x+3 liters, (15/100)(x+3)=0.15(x+3)=0.15x + 0.45 liters is saline


equalize:

0.25x + 0.3 = 0.15x + 0.45

0.25x - 0.15x = 0.45 - 0.3

0.1 x =0.15

x=0.15/0.1= 1.5  (liters)


Answer: 1.5 liters
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Answer:

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Step-by-step explanation:

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rate = 4.04 %

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solution

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put here t = 10 and r = \frac{4.04}{200}

so

present value = \frac{2016(1+\frac{4.04}{200})^10 - 1}{r (1+\frac{4.04}{200})^10}

present value = 18089.96

so

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loan unpaid amount = 21517 - 18089.96

loan unpaid amount = $3427.04

so

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that is express as

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amount = 3427.04 × (1+\frac{4.04}{200})^{10}

amount = 4185.74

so value of buyout is $4185.74

7 0
3 years ago
the midpoint of AB is point P at (-16,6) if point A is at (-10,8) what are the coordinates of point B?
max2010maxim [7]

Answer:

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=> B(-22, 4)

Hope this helps!

:)

8 0
3 years ago
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mariarad [96]

Answer:

The correct answer is C.

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First, we can eliminate A and D since it is obviously only 36 months.

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Answer:

A

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