The equation represented by Ms. Wilson's model is n² + 13n + 40 = (n + 8)(n + 5)
<h3>How to determine the equation of the model?</h3>
The partially completed model is given as:
| n
| n²
5 | 5n | 40
By dividing the rows and columns, the complete model is:
| n | 8
n | n² | 8n
5 | 5n | 40
Add the cells, and multiply the leading row and columns
n² + 8n + 5n + 40 = (n + 8)(n + 5)
This gives
n² + 13n + 40 = (n + 8)(n + 5)
Hence, the equation represented by Ms. Wilson's model is n² + 13n + 40 = (n + 8)(n + 5)
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Answer:
y=mx+c
We have to find the value of m and c.
Let's substitute the value of x and y from the table.
When x=1, y=15,
15= m(1)+c
m +c= 15 ------(1)
Now substitute another set of x and y values.
When x=2, y=24,
24= m(2)+c
2m +c= 24
c= 24 -2m ------(2)
Let me rewrite the two equations so that it is clearer for you to see.
m + c= 15 -----(1)
c = 24 -2m -----(2)
subst. (2) into (1):
m+ 24-2m= 15
-m= 15-24 (bring constants to 1 side, m terms to the other)
-m= -9 (simplify)
m= 9 ( divide by -1 throughout)
subst. m=9 into (2):
c= 24 -2(9)
c= 24-18
c= 6
Thus, the equation is y=9x+6.
When the cat is 3 years old, x=3.
When x=3,
y= 9(3)+6
y= 33.
Hence, the cat is 33 years old in human years.
1.4n + 1.2m
1.4n.....the n represents the number of packs of pencils bought.....and each pack of pencils cost 1.4 (which is the same as 1.40)
1.2m...the m represents the number of pads of paper bought...and each pad of paper cost 1.2 (which is the same as 1.20)
the entire expression represents the total cost spent on buying n packs of pencils and m pads of paper
Hello,
1) Verify if it is a 2 degree.
2) y=ax²+bx+c
Calulate a,b,c by Gauss's methode
a=3, b=0,c=-1
y=3x²-1
