Question

Fill in the Punnett square below to visualize the offspring of a cystic fibrosis carrier and a person who doesn't have cystic fibrosis and isn't a carrier. Use F to denote the normal allele and f to denote the mutated CFR allele. What percentage of their children are likely to have cystic fibrosis? What percentage of their children are likely to be carriers of cystic fibrosis?

Answer 1

Answer:

50% of their children are likely to be carriers of cystic fibrosis

Explanation:

Since the normal allele "F" will be the dominant allele while the mutated CFR allele "f" will be the recessive allele, the gene (pair of alleles) of the person that is a CFR carrier will be "Ff" while that of the normal person who isn't a carrier will be "FF". The attachment shows the crossing between the two parents. From the illustration in the attachment, for every 4 children given birth to, 2 of them will likely be normal, "FF", (not a carrier and doesn't have cystic fibrosis) while 2 others will likely be carriers of cystic fibrosis (Ff). Hence, 50% of their children are likely to be carriers of cystic fibrosis.