Ask question

Ask question

All categories

3 years ago

7

Complete the division.

1 answer:

Verizon [17]3 years ago

8 0

The quotient is 3x^2 -2x +5.

You might be interested in

What is the range of each function given below let g(x)=3^2x?

Naya [18.7K]

Until now, given a function <span>f(x)</span>, you would plug a number or another variable in for x. You could even get fancy and plug in an entire expression for x. For example, given <span>f(x) = 2x + 3</span>, you could find <span>f(y2 – 1)</span> by plugging<span> y2 – 1</span> in for x to get <span>f(y2 – 1) = 2(y2 – 1) + 3 = 2y2 – 2 + 3 = 2y2 + 1</span>.

In function composition, you're plugging entire functions in for the x. In other words, you're always getting "fancy". But let's start simple. Instead of dealing with functions as formulas, let's deal with functions as sets of<span> (x, y)</span><span> points </span>

<span>Hope this awnsers your question</span>

<span>
</span>

<span />

4 0

3 years ago

-5y + 12 + 8y − 6 − 2 = ______ help plz

Sladkaya [172]

Answer:

(combine like terms)

-5y + 12 + 8y − 6 − 2

3y+12-8

3y+4

3 0

3 years ago

I need help on this. Will mark branliest

Romashka-Z-Leto [24]

There is no question or picture.

4 0

3 years ago

Kameryn flips a coin, rolls a 6-sided die, and then spins an 8-section

Levart [38]

Answer:

96 possible outcomes

Step-by-step explanation:

2 x 6 x 8 = 96

8 0

3 years ago

Mai wants to make an open top box by cutting out corners of a square piece of cardboard and folding up the sides. The cardboard

Bumek [7]

Answer:

$V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

The domain for x is all real numbers greater than zero and less than 5 com

Step-by-step explanation:

<em><u>The question is</u></em>

What is the volume of the open top box as a function of the side length x in cm of the square cutouts?

see the attached figure to better understand the problem

Let

x -----> the side length in cm of the square cutouts

we know that

The volume of the open top box is

$V=LWH$

we have

$L=(10-2x)\ cm$

$W=(10-2x)\ cm$

$H=x)\ cm$

substitute

$V(x)=(10-2x)(10-2x)x\\\\V(x)=(100-40x+4x^{2})x\\\\V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

Find the domain for x

we know that

$(10-2x) > 0\\10> 2x\\ 5 > x\\x < 5\ cm$

so

The domain is the interval (0,5)

The domain is all real numbers greater than zero and less than 5 cm

therefore

The volume of the open top box as a function of the side length x in cm of the square cutouts is

$V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

5 0

3 years ago