Answer:
-35
Step-by-step explanation:
you put -78 on top and take put 43 the put the negative back on
<span><span>−<span>a<span><span>4</span><span></span></span></span>−4 <span>a<span>2 is the answer for your question. </span></span></span><span><span></span></span></span>
The given equation of the ellipse is x^2
+ y^2 = 2 x + 2 y
At tangent line, the point is horizontal with the x-axis
therefore slope = dy / dx = 0
<span>So we have to take the 1st derivative of the equation
then equate dy / dx to zero.</span>
x^2 + y^2 = 2 x + 2 y
x^2 – 2 x = 2 y – y^2
(2x – 2) dx = (2 – 2y) dy
(2x – 2) / (2 – 2y) = 0
2x – 2 = 0
x = 1
To find for y, we go back to the original equation then substitute
the value of x.
x^2 + y^2 = 2 x + 2 y
1^2 + y^2 = 2 * 1 + 2 y
y^2 – 2y + 1 – 2 = 0
y^2 – 2y – 1 = 0
Finding the roots using the quadratic formula:
y = [-(- 2) ± sqrt ( (-2)^2 – 4*1*-1)] / 2*1
y = 1 ± 2.828
y = -1.828 , 3.828
<span>Therefore the tangents are parallel to the x-axis at points (1, -1.828)
and (1, 3.828).</span>
Answer:
<em>True
</em>
Step-by-step explanation:
<em>Rate Of Change Of Functions
</em>
Given a function y=f(x), the rate of change of f can be computed as the slope of the tangent line in a specific point (by using derivatives), or an approximation by computing the slope of a secant line between two points (a,b) (c,d) that belong to the function. The slope can be calculated with the formula

If this value is calculated with any pair of points and it always results in the same, then the function is linear. If they are different, the function is non-linear.
Let's take the first two points from the table (1,1)(2,4)

Now, we use the second and the third point (2,4) (3,9)

This difference in values of the slope is enough to state the function is non-linear
Answer: True