Answer:
Inequalities are,
y ≥ 4x + 2
y ≥ 2
Step-by-step explanation:
Solid yellow line of the graph attached passes through two points (0, -2) and (1, 2).
Let the equation of this line is,
y = mx + b
Slope of the line = 
m = 
m = 4
Y-intercept 'b' = -2
Equation of the line will be,
y = 4x - 2
Since shaded area is on the left side of this solid line so the inequality representing this region will be,
y ≥ 4x - 2
Another line is a solid blue line parallel to the x-axis.
Shaded region (blue) above the line will be represented by,
y ≥ 2
Therefore, the common shaded area of these inequalities will be the solution of the given inequalities.
Answer: need point so HA!
Step-by-step explanation:
Correct answer:
15
Explanation:
This problem can be solved by applying the area formula:
Since this question provides the area of the kite and length of one diagonal, plug that information into the equation to solve for the missing diagonal.
Thus the solution is:
60=8×diagonalB2
60×2=8×diagonalB
120=8(diagonalB)
diagonalB=1208=15
Answer:
see below
Step-by-step explanation:
slope = 2 - 1 / 6 - 4 =1/2
Point slope formula (I used point (6,2)):
y - 2 = 1/2 (x - 6)
y = 1/2 x - 1