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mr Goodwill [35]
3 years ago
6

kris is offered a job that pays 9.85$ per hour for a 35 hour work week she will be paid biweekly what will her gross pay be for

each paycheck

Mathematics
2 answers:
Neporo4naja [7]3 years ago
7 0
Answer: $689.50
Explanation:
9.85 x 35 = 344.75
344.75 x 2 = 689.50

You multiply the amount paid by hour by how long she works. Then you multiply the product by 2 because biweekly means every two weeks (bi = 2).
romanna [79]3 years ago
5 0

Answer:

9.85(70)= $689.50 biweekly

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Evaluate the indicated limit algebraically. Change the form of the function where necessary. Please write clearly with descripti
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Answer:

\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3

Step-by-step explanation:

We want to evaluate the limit:

\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}

To do so, we can divide everything by <em>x</em>². So:

=\displaystyle \lim_{x\to \infty}\frac{3+4.5/x^2}{1-1.5/x^2}

Now, we can apply direct substitution:

\Rightarrow \displaystyle \frac{3+4.5/(\infty)^2}{1-1.5/(\infty)^2}

Any constant value over infinity tends towards 0. Therefore:

\displaystyle =\frac{3+0}{1+0}=\frac{3}{1}=3

Hence:

\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3

Alternatively, we can simply consider the biggest term of the numerator and the denominator. The term with the strongest influence in the numerator is 3<em>x</em>²<em>, </em>and in the denominator it is <em>x</em>². So:

\displaystyle \Rightarrow \lim_{x\to\infty}\frac{3x^2}{x^2}

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We acquire the same answer.

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Answer:

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Step-by-step explanation:

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S_{7} = \frac{3(5^7-1)}{5-1}

= \frac{3(78125-1)}{4} = \frac{3(78124)}{4} = 58593

6 0
3 years ago
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