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zhuklara [117]
3 years ago
13

Questions:

Mathematics
2 answers:
puteri [66]3 years ago
8 0
50 F is 10 C

45 C is 113 F
ryzh [129]3 years ago
5 0

Answer:

50 into celsius is 10

45 into fahrenheit is 113

Step-by-step explanation:

You might be interested in
write and equation of the line parallel to the line  2 x + 4 y = 20 2 x + 4 y = 20 and containing the point  ( −
MAXImum [283]

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m represents the slope of the line

c represents the y intercept

The equation of the given line is

2x + 4y = 20

4y = - 2x + 20

Dividing through by 4, it becomes

y = - x/2 + 5

Comparing with the slope intercept form, slope = - 1/2

If two lines are parallel, it means that they have the same slope. Therefore, the slope of the line passing through (- 6, 3) is - 1/2

To determine the y intercept, we would substitute m = - 1/2, x = - 6 and y = 3 into y = mx + c. It becomes

3 = - 1/2 × - 6 + c

3 = 3 + c

c = 3 - 3 = 0

The equation becomes

y = - x/2

4 0
3 years ago
Please please please.
sesenic [268]
the possibilities are probably b, using the elimination method
4 0
2 years ago
Geometry help?<br> 24/10<br> 10/24<br> 24/26<br> 10/26
olasank [31]
24/26 or opposite over adjacent. The answer is C
8 0
3 years ago
Which of the following sets could be represented by the given Venn diagram? S = {multiples of 4} T = {8, 12, 20} S = {Mercury, V
Firdavs [7]

Answer:

The answer is C S = {reptiles} T = {mammals}

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the perimeter of this quadrilateral?<br> (5,5)<br> (2, 4)<br> (4, 1)<br> (6, 1)
lbvjy [14]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}

BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}

DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89

8 0
2 years ago
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