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3 years ago

Simplify the algebraic expression to simplest form by combining like terms. c+c+c+d+c+d+d+c

Mathematics

2 answers:

Elodia [21]3 years ago

6 0

Answer:

5c+3d

Step-by-step explanation:

5 x c

3 x d

Korvikt [17]3 years ago

4 0

Yup 5c + 3d just add all the c’s then add all the d’s

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Two friends are biking. Greta starts at mile marker S on a bike trail and is biking at a speed of 12 miles per hour The table sh

Alinara [238K]

The distance covered by Greta after biking at a speed of 12 miles per hour for x hours is 12x miles.

<h3>What is speed?</h3>

Speed is the ratio of distance travelled to time taken. It is given by:

Speed = distance / time

Greta starts at mile marker S on a bike trail and is biking at a speed of 12 miles per hour. If she biked for x hours:

Distance covered = 12 mph * x = 12x miles

The distance covered by Greta after biking at a speed of 12 miles per hour for x hours is 12x miles.

Find out more on speed at: brainly.com/question/4931057

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2 years ago

At the beginning of the month, Sheryl had a balance of $120 in her checking account. She then made a purchase for $80, using her

Rama09 [41]

$80

add what you took out

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2 years ago

If I throw a die, find the probability of throwing an odd number or a number less than 3.

Annette [7]

If you throw a die, this is what you could get:

1, 2, 3, 4, 5 or 6.

--------------

Odd Numbers: 1, 3, 5

Numbers less than Three: 1, 2

---------------

Possibility of getting 1, 2, 3 or 5:

4/6 which translates into 2/3.

---------------

Answer:

2/3

5 0

3 years ago

Helppp meeeeeeeeeeeeeeeeeee

Veronika [31]

Answer:

First

Step-by-step explanation:

5 0

3 years ago

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Simplify the expression csc(-x)/1+tan^2x)

Charra [1.4K]

Assuming ya meant $\frac{csc(-x)}{1+tan^2(x)}$

to slimplify, we use a variation of the pythagorean identity and a decomposition into the sin and cos

for the pythaogreaon identity
$cos^2(x)+sin^2(x)=1$
divide both sides by $cos^2(x)$
$1+tan^2(x)=sec^2(x)$ since $\frac{sin(x)}{cos(x)}=tan(x)$
subsitute
$\frac{csc(x)}{sec^2(x)}$

recall that $csc(x)=\frac{1}{cos(x)}$
also that cos(x) is an even function and thus cos(-x)=cos(x)
therfore $csc(-x)=\frac{1}{cos(-x)}=\frac{1}{cos(x)}=csc(x)$
so we get

$\frac{csc(x)}{sec^2(x)}$
decompose them into $\frac{1}{cos(x)}$ and $\frac{1}{sin^2(x)}$ to get $\frac{\frac{1}{cos(x)}}{\frac{1}{sin^2(x)}}$
multiply by $\frac{sin^2(x)}{sin^2(x)}$ to get
$\frac{sin^2(x)}{cos(x)}$
we can furthur simlify to get
$(\frac{sin(x)}{cos(x)})(sin(x))=tan(x)sin(x)$
the expression simplifies to tan(x)sin(x)

5 0

3 years ago

Read 2 more answers