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4 years ago

Solve S= 2HW + 2HL + 2WL for L.

Mathematics

1 answer:

puteri [66]4 years ago

8 0

To solve for L, you need to isolate/get the variable "L" by itself in the equation:

S = 2HW + 2HL + 2WL Subtract 2HW on both sides

S - 2HW = 2HW - 2HW + 2HL + 2WL

S - 2HW = 2HL + 2WL Take out the "L" in 2HL and 2WL

S - 2HW = L(2H + 2W) Now divide (2H + 2W) to get "L" by itself

$\frac{S-2HW}{2H +2W} =\frac{L(2H+2W)}{2H+2W}$

$\frac{S-2HW}{2H+2W} =L$

I think you can stop here, but if you need or want to simplify:

$\frac{S}{2H+2W} -\frac{HW}{H+W} =L$ which looks longer so I don't know if you need to do this

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