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Lorico [155]
3 years ago
15

Jason states that -5.0 is not an integer because it is a decimal. Is he correct? Why or why not?

Mathematics
1 answer:
gulaghasi [49]3 years ago
5 0

Answer:

The answer is No, he's incorrect

Step-by-step explanation:

Because -5.0 is still -5 so therefore it makes -5.0 an integer

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Please help me i really need help please help please
solong [7]

Answer:

3.605 ft is the answer.

Step-by-step explanation:

Applying Pythagoras theorem,

a^2 + b^2 = c^2

2^2 + 3^2 = c^2

4 + 9 = c^2

13 = c^2

3.605 = c

therefore, the answer is 3.605.

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8 0
3 years ago
Mr. Gubareff gave his class 15 minutes to read. Sabira read 6 ¼ pages in that time. At what rate, in pages per hour, did Sabira
creativ13 [48]

Answer:

I think its 25 (proceed with caution)

Step-by-step explanation:

15×4=60 so basically 6.25×4=25

6.25 = 6 1/4

4 0
3 years ago
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{[14-2×3]-[18÷(12-3)]}+{42-11×3+[(65-9×5)+3]}
natali 33 [55]
Use Bidmas, solve all the inner brackets (), with first division, then multiplication then addition then subtraction
5 0
3 years ago
Suppose a white dwarf star has a diameter of approximately 1.8083 to the power of 4 km. Use the formula 4n to the power of 2 to
aivan3 [116]

ANSWER:

The surface area of the star is 3.2700 x 10^{8} square kilometres.

EXPLANATIONS:

Diameter of the star = 1.8083 x 10^{4} Km.

Surface area of the star = 4n^{2}

Where n is the radius of the star.

So that;

n = \frac{ 1.8083 * 10^{4} }{2}

   = 0.90415 x 10^{4}

n =  0.90415 x 10^{4} Km

Thus,

Surface area = 4 x (0.90415*10^{4} )^{2}

                     = 326994889

Surface area = 3.2700 x 10^{8} km^{2}

Therefore, the surface area of the star is 3.2700 x 10^{8} square kilometres.

4 0
3 years ago
I need help with this
rodikova [14]
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5 0
3 years ago
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