To find the pre image you need to back track on the image. To get to the image you used (x-6,y+8). Now you need to use the exact opposite to get back to the pre image. For this you would change the signs to look like (x+6,y-8). Now we just apply this to (-4,1).
(-4+6,1-8)
(2,-7) should be the pre image point.
Answer:
there is nothing atttached or no options given
Step-by-step explanation:
Answer:
See below.
Step-by-step explanation:
It transforms to the Pythagoras theorem.
c^2 = a^2 + b^2 - 2ab cos C
If C = 90, cos C = zero so the last term disappears.
c^2 = a^2 + b^2 - 2ab * 0
c^2 = a^2 + b^2.
Answer:
D. y = 4x - 6
Step-by-step explanation:
The equation that is perpendicular to the line MN should have a slope that when multiplied by the slope of line MN will result to negative one. Therefore,
Therefore,
m₁ × m₂ = -1
Using the 2 coordinates of MN let's find the slope,
(-7, 6)(5, 3)
Therefore,
m₁ = 3 - 6 / 5 - (-7) = -3 / 12 = - 1 / 4
The equation that represent a line perpendicular to the line MN is
y = 4x - 6 because the slope slope(m₂) is 4.
From our formula,
4 × - 1 / 4 = - 1
So, option D meets the requirement.
