Answer:
The answer is always
Hope this helps......... :)
Answer:
Group A, because seven children have a forearm length longer than 10 inches
Step-by-step explanation:
Create the dot plots based on the given information (please see attached images).
Group A = blue dots
Group B = red dots
From inspection of the attached dot plots, we can see that Group A appears to have the longer average forearm length. This is because 7 children have a forearm length of longer than 10 inches.
To calculate the average forearm length, sum all data values and divide by the total number of data values.
![\textsf{Average of Group A}=\dfrac{ 3 \times 10 + 4 \times 11 + 3 \times 12}{10}=11](https://tex.z-dn.net/?f=%5Ctextsf%7BAverage%20of%20Group%20A%7D%3D%5Cdfrac%7B%203%20%5Ctimes%2010%20%2B%204%20%5Ctimes%2011%20%2B%203%20%5Ctimes%2012%7D%7B10%7D%3D11)
![\textsf{Average of Group B}=\dfrac{ 3 \times 9 + 5\times 10+ 2\times 11}{10}=9.9](https://tex.z-dn.net/?f=%5Ctextsf%7BAverage%20of%20Group%20B%7D%3D%5Cdfrac%7B%203%20%5Ctimes%209%20%2B%205%5Ctimes%2010%2B%202%5Ctimes%2011%7D%7B10%7D%3D9.9)
Thus proving that Group A has the longer average former length.
Use the zeroes to figure this out... x=-18, y=9
Answer: D
Step-by-step explanation:
h(x) is f(x) for x moving 4 units right.
h(x)=f(x-4) =√(x-4)
Answer D