Answer: (D) Carbon Dioxide
Explanation: Carbon dioxide, the byproduct of cell respiration,<u> is small enough to readily diffuse out of a cell. </u>Small uncharged lipid molecules can pass through the lipid innards of the membrane.
Answer:
Protons, neutrons, and electrons.
Explanation:
Answer:
35%
Explanation:
If two genes are 30 map units apart, 30% of the produced gametes will be recombinant.
A mating between an individual homozygous dominant for both traits (AB/AB) and one homozygous recessive for both traits (ab/ab) is conducted.
The F1 will be heterozygous for both genes: AB/ab.
The F1 progeny is then test-crossed to a homozygous recessive individual:
<h3>AB/ab X ab/ab</h3>
<u>The possible offspring will be:</u>
- Parental (70%): AB/ab and ab/ab
- Recombinant (30%): Ab/ab and aB/ab
Since 30% of all the gametes produced by the F1 individual will be recombinant, 70% will be parental. As there are two types of parental gametes, each of them will have a frequency of 35%.
<u>The offspring that will have a dominant phenotype for both traits has the genotype AB/ab with a proportion of 35%.</u>
The answer to your question is A., as the random movement is a movement
Answer:
Please find the expected genotypes and phenotypes of the progenies of each cross below.
Explanation:
In the MN blood-group locus of the gene, alleles LM and LN exhibit codominance i.e one allele is not dominant or recessive to the other, hence, they are both expressed when they occur in a heterozygous state (MN).
Considering the following crosses (find the punnet square attached);
a)LMLM x LMLN - The progeny are LMLM and LMLN in the genotypic ratio 1:1. Phenotypic ratio is Blood type M (1) : blood type MN (1)
b) LNLN x LNLN - The progeny are all LNLN offsprings with a phenotypic and genotypic ratio 4:0. All offsprings will have a blood type N (4)
c) LMLN x LMLN - The progenies are LMLM, LMLN and LNLN in the genotypic ratio 1:2:1 respectively. The phenotypic ratio is Blood type M (1) : L
Blood type MN (2) : Blood type N (1)
d) LMLN x LNLN - The progeny are LMLN and LNLN with genotypic ratio 1:1 and phenotypic ratio blood type MN (1) : blood type N (1)
e) LMLM x LNLN - The progeny are all LMLN offsprings with penotypic ratio blood type MN (4)