Question

Write a function rule for the area of rectangle whose length is 2ft more than its width. What is the area of the rectangle when its width is 11ft

Answer 1

According to the problem, the length is 2 feet more than its width, which is expressed as the following function

$l=w+2$

If the width is x, then the length is x+2.

We can express the following function for the area

$A(x)=x(x+2)$

Let's replace the width x = 11 ft.

$A(11)=11\cdot(11+2)=11(13)=143$

Hence, the area is 143 square feet.

The function for the area is

$A(x)=x(x+2)$

Where x represents the width.