Given:
Consider the vertices of the triangle are (4,4) (6,7) and (8,0).
The triangle is dilated by a scale factor of 3.
To find:
The vertices of the new triangle after dilation.
Solution:
If a figure is dilated by scale factor k with origin as the center of dilation, then the rule of dilation is:

The given figure is dilated by scale factor 3 with origin as the center of dilation, then the rule of dilation is:

Let the vertices of the triangle are A(4,4), B(6,7) and C(8,0).
Using this rule of dilation, we get


Similarly,


And,


The vertices of the new triangle are (12,12), (18,21), (24,0).
Therefore, the correct option is 4.