Answer:
Let the total numbers of cars be ten then the total cars produced in one week would be 50
Probability of deficient cars on Monday = 4/10
Probability of deficient cars on Tuesday =1/10
Probability of deficient cars on Wednesday = 1/10
Probability of deficient cars on Thursday = 1/10
Probability of deficient cars on Friday = 3/10
Probability ( deficient car)= 10/50 or 1/5
Probability that it produced on Monday 4/10*1/5= 4/50= 2/25= 8/100= 0.08 or 8%
Probability of deficient cars on Monday = 4/10* 12/100= 48/1000= 0.048or 4.8%
Probability of deficient cars on Tuesday =1/10 *22/100= 22/1000= 0.022 or 2.2%
Probability of deficient cars on Wednesday = 1/10*22/100=22/1000= 0.022 or 2.2%
Probability of deficient cars on Thursday = 1/10*22/100=22/1000= 0.022 or 2.2%
Probability of deficient cars on Friday = 3/10*22/100= 66/1000= 0.066 or 6.6%
give me more details. that's a bit confusing
Answer:
m(∠C) = 18°
Step-by-step explanation:
From the picture attached,
m(arc BD) = 20°
m(arc DE) = 104°
Measure of the angle between secant and the tangent drawn from a point outside the circle is half the difference of the measures of intercepted arcs.
m(∠C) = ![\frac{1}{2}[\text{arc(EA)}-\text{arc(BD)}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%5Ctext%7Barc%28EA%29%7D-%5Ctext%7Barc%28BD%29%7D%5D)
Since, AB is a diameter,
m(arc BD) + m(arc DE) + m(arc EA) = 180°
20° + 104° + m(arc EA) = 180°
124° + m(arc EA) = 180°
m(arc EA) = 56°
Therefore, m(∠C) = 
m(∠C) = 18°
Answer:
4 goals
Step-by-step explanation:
Let:
x = number of total goals scored in first 5 games
y = answer = number of goals in 6th game
formula:
average = sum of individual parts / total number of parts
average_5_games = x / 5 = 2.8
solve for x:
x = 2.8 × 5 = 14
average_6_games = (x + y) / 6 = 3
solve for y:
x + y = 6 × 3 = 18
y = 18 - x = 18 - 14 = 4
