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nasty-shy [4]
4 years ago
5

Los lados de un triángulo rectángulo miden 6m, 8m y 10m. respectivamente. ¿Cuánto medirán los catetos de un triángulo semejante

al primero si su hipotenusa mide 15m?
Mathematics
1 answer:
OlgaM077 [116]4 years ago
5 0

Answer: Los catetos medirán 12m y 9m.

Step-by-step explanation:

Bueno, sabemos que los lados de nuestro triangulo son 6m, 8m y 10m.

Podemos usar relaciones trigonométricas para encontrar los ángulos de este triangulo.

Cos(X) = cateto adyacente/hipotenusa

Si tomamos al cateto adyacente como 8m, tenemos:

Cos(X) = 8m/10m

X = Acos(8/10)  

Esto nos dice que para que nuestro otro triangulo rectángulo sea equivalente al primero, entonces los nuevos catetos C1  y C2 tienen que ser tal que los cocientes entre los catetos y la hipotenusa se mantengan constantes:

C1/15m = 8m/10m

C1 = (8/10)*15m = 12m

C2/15m = 6m/10m  

C2 = (6/10)*15m = 9m.

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