I believe this is right:
Least: 8 (length) x 1 (width) = 8
Greatest: 5 (length) x 4 (width) = 20
Difference: 20 - 8 = 12
He answer is d which is 25
Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
<h3>Given</h3>
... f(x) = x² -4x +1
<h3>Find</h3>
... a) f(-8)
... b) f(x+9)
... c) f(-x)
<h3>Solution</h3>
In each case, put the function argument where x is, then simplify.
a) f(-8) = (-8)² -4(-8) +1 = 64 +32 + 1 = 97
b) f(x+9) = (x+9)² -4(x+9) +1
... = x² +18x +81 -4x -36 +1
... f(x+9) = x² +14x +46
c) f(-x) = (-x)² -4(-x) +1
... f(-x) = x² +4x +1
