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3 years ago

How many solutions does the equation have y=2x^2+3x-10=0

Mathematics

1 answer:

Natali [406]3 years ago

8 0

Answer:it has two

Step-by-step explanation: x =(3-√89)/4=-1.608

x =(3+√89)/4= 3.108

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What is the axis of symmetry of the parabola y= 1/3 (x-10)^2 - 6

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Answer:

The equation of the axis of symmetry is equal to

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Step-by-step explanation:

we have

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Which of the following is a solution of x^2 + 2x + 4?

Kaylis [27]

Answer:

$\displaystyle x_1=-1+\sqrt{3}i$

$\displaystyle x_2=-1-\sqrt{3}i$

Step-by-step explanation:

<u>Second-Degree Equation</u>

The second-degree equation or quadratic equation has the general form

$ax^2+bx+c=0$

where a is non-zero.

There are many methods to solve the equation, one of the most-used is by using the solver formula:

$\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

The equation of the question has the values: a=1, b=2, c=4, thus the values of x are

$\displaystyle x=\frac{-2\pm \sqrt{2^2-4\cdot 1\cdot 4}}{2\cdot 1}$

$\displaystyle x=\frac{-2\pm \sqrt{-12}}{2}$

Since the square root has a negative argument, both solutions for x are imaginary or complex. Simplifying the radical

$\displaystyle x=\frac{-2\pm 2\sqrt{-3}}{2}=-1\pm\sqrt{3}i$

The solutions are

$\displaystyle x_1=-1+\sqrt{3}i$

$\displaystyle x_2=-1-\sqrt{3}i$

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