Answer: Hello!
A second order differential equation has the next shape:

where p(t), q(t) and g(t) are functions of t, that can be constant numbers for example.
And is called homogeneus when g(t) = 0, so you have:

Then a second order differential equation is homogeneus ef every term involve either y or the derivatives of y.
Answer:
19.14lb
Step-by-step explanation:
given: s is the midpoint of rt
definition of midpoint: rs st
given: st xy
transitive property of congruence: rs xy
Because the two angles on the right add to 180 degrees, we can create this system:

We can also prove that

, which, when solved, shows that

.
When plugged in to the original equation, we find that y = 105 degrees.
B,D is the answer for your question