Answer:
The energy used in 3.5 hours = 5.25 kilowatts
Step-by-step explanation:
Energy used by electric kettle:
kilowatts
Time taken by electric kettle:
Electric kettle's rate in kilowatts per hour can be calculated by dividing the spent energy i.e. 2.25 kilowatts by the time taken i.e. 1.5 hours.
Therefore,
Electric kettle's rate = 2.25 kilowatts / 1.5 hour
= 1.5 kilowatts per hour
Thus, the energy used in 3.5 hours = 1.5 × 3.5
= 5.25 kilowatts
Therefore, the energy used in 3.5 hours = 5.25 kilowatts
Hey there!
The answer is false. A 90 degree angle is called a right triangle. Any angle less than 90 degree is called an acute angle. Any angle more than 90 degree is called an obtuse angle
Answer:
The win percentage decreased by 10%
Step-by-step explanation:
First you need to fin the total games played right before Melissa got Injured
41+23=64
Then you need to find the win percentage by making a fraction of wins over total games
wins/total games = 41/64 = 64%
Then you need to find the number of games played after Melissa got injured
54-41 = 13 wins
34-23 = 11 losses
13+11 = 24 total games played without Melissa
You find that win percentage similarly to the first time
wins/total games = 13/24 = 54%
Then you find the difference in the percentages and there you have it!!
64% - 54% = 10%
It decreased as well therefore the answer is...
It decreased by 10%
Answer:
<em>− 2sin(b) / cos(2b)</em>
Step-by-step explanation:
DIFFERENTIATE W.R.T. B is a different method entirely
We simply add together the numerators and set with 2cos
then keep this number and add to sinb and square it.
then repeat initial 2 + cosb ^2 but instead of multiplying its add.
Then set the whole division to -sin (2b) squared then +1
<em> − 2cos(b)(3(sin(b))^2+(cos(b))^2) / −(sin(2b)) ^2 +1 </em>
Answer:
d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)
Step-by-step explanation:
d²y/dx² = (-2y² − x²) / (4y³)
Take the derivative (use quotient rule and chain rule):
d³y/dx³ = [ (4y³) (-4y dy/dx − 2x) − (-2y² − x²) (12y² dy/dx) ] / (4y³)²
d³y/dx³ = [ (-16y⁴ dy/dx − 8xy³ − (-24y⁴ dy/dx − 12x²y² dy/dx) ] / (16y⁶)
d³y/dx³ = (-16y⁴ dy/dx − 8xy³ + 24y⁴ dy/dx + 12x²y² dy/dx) / (16y⁶)
d³y/dx³ = ((8y⁴ + 12x²y²) dy/dx − 8xy³) / (16y⁶)
d³y/dx³ = ((2y² + 3x²) dy/dx − 2xy) / (4y⁴)
Substitute:
d³y/dx³ = ((2y² + 3x²) (-x / (2y)) − 2xy) / (4y⁴)
d³y/dx³ = ((2y² + 3x²) (-x) − 4xy²) / (8y⁵)
d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)
