Answer:
a). Area of the parallelogram = 8 cm²
b). Area of both the triangles = 4 cm²
Step-by-step explanation:
a). Area of the given parallelogram ABCD = Base × Height
= DC × (Vertical distance between
AB and DC)
= 9 × 
= 8 ft²
b). If we decompose this parallelogram into two triangles ΔABC and ADC by a diagonal AC,
Area of both the triangles will be equal.
(Since, diagonal of a parallelogram divides the parallelogram into two equal triangles)
Therefore, area of ΔABC = Area of ΔADC = 4 ft²
Before we do this problem, let's go over a little algebra terminology.
The number in front of your variable is called your <em>coefficient </em>and notice that the <em>x</em> at the end of the problem does not have a coefficient.
When that happens, when there is no number in front of your variable, you can put a 1 there to fill that position. So -x can be thought of as -1x.
Next let's change all our minus signs to plus negatives.
So the problem reads 3x + 5 + 7x + -3 + -1x + 2.
Now let's simplify this by combining like terms.
We can combine our "x" terms first.
3x + 7x + -1x simplifies to +9x.
Now, 5 + -3 + 2 simplifies to 4.
So our answer is 9x + 4.
Answer:
(x + 1)/4x² + 4(x + 1)/4x²
Step-by-step explanation:
x+1/4x² + x+1/x²
The above can be simply as follow:
Find the least common multiple (LCM) of 4x² and x². The result is 4x²
Now Divide the LCM by the denominator of each term and multiply the result with the numerator as show below:
(4x² ÷ 4x²) × (x + 1) = x + 1
(4x² ÷ x²) × (x + 1) = 4(x + 1)
x+1/4x² + x+1/x² = [(x + 1) + 4(x + 1)]/ 4x²
= (x + 1)/4x² + 4(x + 1)/4x²
Therefore,
x+1/4x² + x+1/x² = (x + 1)/4x² + 4(x + 1)/4x²
