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3 years ago

1. The sum of any two integers is a whole number.

Mathematics

1 answer:

Nimfa-mama [501]3 years ago

8 0

2. |2+(-4)| = 2 |2| + |(-4)| = 6

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You have a credit card that has a balance of $3,589.90 and a credit limit of $5,000. How much is the balance over the acceptable

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4 years ago

Trever is a salesperson who is paid a monthly salary of $500 plus a 2% commission on sales. the i come base on x sales (in dolla

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He makes $10 off of sales

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3 years ago

Use the graph of the following function (x) to find the value. <br> f(1)

kvv77 [185]

From the graph of the given function , the value of f(1) = -1.

As given in the question,

From the graph of the given function,

Two coordinates from the graph are as follow:

( x₁ , y₁) = (1, -1)

( x₂ , y₂ ) = ( 0, -3 )

Equation of the line representing the function is given by:

(y - y₁) /(x-x₁) = ( y₂ -y₁)/ (x₂ -x₁)

⇒(y +1)/ (x-1) = (-3 +1)/ (0-1)

⇒ (y +1)/ (x-1) = 2

⇒y +1 = 2x -2

⇒ y = 2x -3

To get the value of x we have,

y = f(x)

⇒f(x) = 2x -3

⇒f(1) = 2(1) -3

⇒f(1) = -1

Therefore, from the graph of the given function , the value of f(1) = -1.

Learn more about graph here

brainly.com/question/17267403

#SPJ1

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1 year ago

What is 2,731 divided by 31 with a remainder

masha68 [24]

Answer:?

Step-by-step explanation:

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3 years ago

Consider the probabilities of people taking pregnancy tests. Assume that the true probability of pregnancy for all people who ta

Valentin [98]

Using conditional probability, it is found that there is a 0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

<h3>What is Conditional Probability?</h3>

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem, the events are:

Event A: Positive test result.

Event B: Pregnant.

The probability of a positive test result is composed by:

99% of 10%(truly pregnant).

2% of 90%(not pregnant).

Hence:

$P(A) = 0.99(0.1) + 0.02(0.9) = 0.117$

The probability of both a positive test result and pregnancy is:

$P(A \cap B) = 0.99(0.1)$

Hence, the conditional probability is:

$P(B|A) = \frac{0.99(0.1)}{0.117} = 0.8462$

0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

You can learn more about conditional probability at brainly.com/question/14398287

7 0

2 years ago