1. The sum of any two integers is a whole number.
1 answer:
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Answer:
Graph the exponential function.
Step-by-step explanation:
to make a sketch of this graph. We're gonna make a table of values. I think that's probably our best route. So we'll do a couple negative values, but I'm gonna actually start at 08 to 0. Power zero. And I'm sorry. 80 parts one and one times negative. Three is negative. Three eight to the first. Power is eight and eight times negative. Three is negative. 24 8 X squared is 64 64 times negative. Three is on negative. 192. Okay, I think that's plenty. E to the negative. First power is 18 and 1/8 times negative. Three is negative. 3/8 and eight to the negative. To power is 1 64th times negative. Three is negative. 3 60 force. Okay, I think we can see where that's going. Is getting really close to zero. So as faras my graph here, I'm gonna focus on the fourth quadrant, I think. All right. So we got our X and y axis here. We're starting at 01 and to and we'll also do negative one. And negative two aren't horizontally, vertically. I do. I want to scale this whole the way to 1 92 I guess I will. Um, so whatever it is scaled by, maybe twenties. Yeah, let's do that. 20 40 60 8120 40 60 8200. So there's negative. 200? Um, negative. 1 80 Negative 1 60? Nope. That's not right. Because I scaled by twenties didn't. So this is actually negative. 1 60 This one's negative. 1 20 This one's negative. 80. And this is negative. 40. There we go. All right now a plot. These points to negative 1 92 is practically to 200 one. Negative. 24 is all the way over here. Zero negative three is practically on the X axis The way I have this, and same with those fractional values. They're practically on the X axis. So let's start almost parallel to the X axis because it's never actually touch step than its we don't ever. Slowly and then it starts going down rapidly, decreasing in value to the point where it's almost vertical, but it never will get vertical, so there's a decent sketch of y equals negative three times eight to the power of acts
Answer:
68.26% probability that the number of jobs finished on time is within 1 standard deviation of the mean.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Looking at a random sample of 8 jobs that it has contracted, find the probability that x (number of jobs finished on time) is within one standard deviation of the mean.
Within 1 standard deviation of the mean is from Z = -1 to Z = 1. So this probability is the pvalue of Z = 1 subtracted by the pvalue of Z = -1.
Z = 1 has a pvalue of 0.8413
Z = -1 has a pvalue of 0.1587
So there is a 0.8413 - 0.1587 = 0.6826 = 68.26% probability that the number of jobs finished on time is within 1 standard deviation of the mean.