Simple,
writing out the problem...
Simplify it...
-4x(6+5-1)
-4x(11-1)
-4x(10)
-40x
Making it look like...
Cancel out the common factors...
Thus making the answer:
.
Answer:
y= -5x +24
Step-by-step explanation:
<u>Slope-intercept form</u>
y= mx +c, where m is the slope and c is the y-intercept.
Given that the slope is -5, m= -5.
Substitute m= -5 into the equation:
y= -5x +c
To find the value of c, substitute a pair of coordinates that the line passes through into the equation:
When x= 3, y= 9,
9= -5(3) +c
9= -15 +c
c= 9 +15
c= 24
Thus, the equation of the line is y= -5x +24.
It takes 4.3 seconds for the rocket to return to earth.
The equation is:
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height. We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42. This gives us:
We will use the quadratic formula to solve this. The quadratic formula is:
Plugging in our information we have:
x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
Answer:
C
Step-by-step explanation:
look up rules of multiplying radicals.
You can multiply the radicands (the number inside the square root) then take the square root of the new number.
3*21 = 63
Factor 63 into 3*3*7
Pull out 3^2 from inside the square root
leaves you with 3sqrt7 or answer C
3y^2 and -3/4y^2
5x and 2/3x
12x^2
