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3 years ago

X Y=x+2 ordered pair

Mathematics

1 answer:

Leokris [45]3 years ago

6 0

Answer:

yes, i believe so

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If fx) = 3x-2], what is f(59)?

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F(59)=3x-2
f(59)=3(59)-2
f(59)=177-2
f(59)=175

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3 years ago

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Eduardwww [97]

I think c would be the correct answer

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3 years ago

Divide by using long division. (x²-x-6) = (x-3)

Fudgin [204]

Answer: x + 2

Step-by-step explanation:

Given the equation to solve by long division :

Divide x² - x - 6 by x - 3

x in the divisor is used to divide the x² in the Dividend to obtain a value of x as the quotient. The quotient value is multiplied by each value in the Dividend and so on.

This steps taken obtain the quotient is clearly shown in the picture attached.

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3 years ago

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Mariana [72]

Answer:

12) 26x^2+22x+25

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5 0

3 years ago

Read 2 more answers

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$

Thus, the required solution is

$y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.$

6 0

3 years ago