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3 years ago

Help plz I will give brainliest!!!

Mathematics

1 answer:

Eduardwww [97]3 years ago

3 0

I think c would be the correct answer

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What method can be used to prove the triangles below are congruent?

Nadusha1986 [10]

Answer: D) Not possible

SSA is not a valid congruence theorem. Note how the angles are not between the congruent sides.

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3 years ago

How do I work this problem

AnnyKZ [126]

Start by writing out the equation then combining like terms then its a simple 2 step equation.

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4 years ago

Read 2 more answers

The weight for crates of eggs is normally distributed with a mean weight of 34.6 pounds and a standard deviation of 2.8 pounds.

Bingel [31]

Answer:

0.5532

Step-by-step explanation:

P( 31<X<35.7)

P(X>31)= P(Z>(31-μ)/σ)

= P(Z>(31-34.6)/2.8)

= P(Z> -1.2857)

P(X<35.7)= P(Z<(35.7-μ)/σ)

= P(Z<(35.7-34.6)/2.8)

=P(Z< 0.392857)

From z-distribution table

P(Z< -1.29)= 0.09853

p(Z< 0.39) = 0.65173

P( 31<X<35.7)= P(Z<0.39)- P(Z<-1.29)

= 0.65173- 0.09853

=0.5532

6 0

4 years ago

Read 2 more answers

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

irakobra [83]

Answer:

We need a sample size of at least 383.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

85% confidence level

So $\alpha = 0.15$ , z is the value of Z that has a pvalue of $1 - \frac{0.15}{2} = 0.925$ , so $Z = 1.44$ .

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 85% confidence level with an error of at most 0.03

We need a sample size of at least n.

n is found with $M = 0.03, \pi = 0.21$