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Amiraneli [1.4K]
3 years ago
6

Help i dont understand this

Mathematics
1 answer:
Andreyy893 years ago
4 0

Step-by-step explanation:

you substitute the given values in s-row for s in the function, then calculate the results and fill the blanks in f(s)-row

s=0 --> f(s) = |0-2| / (0-2) = -1

s=1 --> f(s) = -1

s=9/2 --> f(s) = 1

s=11/2 --> f(s) = 1

s=6 --> f(s) = 1

In fact, there's a more shorter way to do this

You see that:

|x-2| = x-2 when x≥2

|x-2| = -(x-2) when x<2

Therefore:

f(s) = 1 for all x≥2

f(s) = -1 for all x<2

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Answer:

Slope =-1/3

Step-by-step explanation:

(3,2)..... x1 =3, y1=2

(-3,4).... x2=-3, y2 =4

Slope=(y2-y1) /(x2-x1)

Slope=(4-2) /(-3-3)

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Slope=-1/3

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Step-by-step explanation:

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Solve the equation below. Pls include work<br><br><br><br> 28.10 = 15.5 + 5x
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Answer:

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2 years ago
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if i have 19 friends they each want 3 slices of cake i have 38 slices how do i divide and get a simple remainder.
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3 years ago
The probability that your call to a service line is answered in less than 30 seconds is 0.85. Assume that your calls are indepen
aev [14]

Answer:

a) 0.1720

b) 0.8298

c) 19

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.85

(a) If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is P(X = 9) when n = 12.

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{12,9}.(0.85)^{9}.(0.15)^{3} = 0.1720

(b) If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is P(X \geq 16) when n = 20

So

P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 16) = C_{20,16}.(0.85)^{16}.(0.15)^{4} = 0.1821

P(X = 17) = C_{20,17}.(0.85)^{17}.(0.15)^{3} = 0.2428

P(X = 18) = C_{20,18}.(0.85)^{18}.(0.15)^{2} = 0.2293

P(X = 19) = C_{20,19}.(0.85)^{19}.(0.15)^{1} = 0.1368

P(X = 20) = C_{20,20}.(0.85)^{20}.(0.15)^{0} = 0.0388

So

P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.1821 + 0.2428 + 0.2293 + 0.1368 + 0.0388 = 0.8298

(c) If you call 22 times, what is the mean number of calls that are answered in less than 30 seconds? Round your answer to the nearest integer.

The expected value of the binomial distribution is:

E(X) = np

In this question, we have n = 22

So

E(X) = 22*0.85 = 18.7

The nearest integer to 18.7 is 19.

7 0
3 years ago
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