It is b dont be fooled its not c it is b

To determine the number of trout in a lake, a conservationist catches 136 trout, tags them and throws them back into the lake.

Marina CMI [18]

Im not sure sorry, I hope you find your answer

8 0

2 years ago

Jason and Alison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of

Shalnov [3]

Answer:

$Owl= 67.14ft$

Step-by-step explanation:

See comment for complete question.

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

$22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}$

$22^{\circ} 8'6'' = 22.135^{\circ}$

$30^{\circ} 40'30'' = 30 + \frac{40}{60} + \frac{30}{3600}$

$30^{\circ} 40'30'' = 30.675^{\circ}$

Considering Jason's position:

$tan(22.135^{\circ}) = \frac{H}{x + 48}$

Where x = distance between the tree and Alison

Make H the subject

$H = (x + 48)tan(22.135^{\circ})$

Considering Alison's position

$tan(30.675^{\circ}) = \frac{H}{x}$

Make H the subject

$H = xtan(30.675^{\circ})$

$H = H$

$(x + 48)tan(22.135^{\circ}) = xtan(30.675^{\circ})$

$(x + 48) *0.4068 = x* 0.5932$

Open bracket

$x *0.4068 + 48 *0.4068 = 0.5932x$

$0.4068x + 19.5264 = 0.5932x$

Collect Like Terms

$-0.5932x+0.4068x = -19.5264$

$-0.1864x = -19.5264$

$0.1864x = 19.5264$

Make x the subject

$x = \frac{19.5264}{0.1864}$

$x = 104.76$

Substitute 104.76 for x in $H = xtan(30.675^{\circ})$

$H = 104.76 * tan(30.675^{\circ})$

$H = 104.76 * 0.5932$

$H = 62.14$

The above represents the height of the tree.

The height of the owl is:

$Owl= H + 5$

$Owl= 62.14 + 5$

$Owl= 67.14ft$

7 0

2 years ago

A circular pen has an area of 64<img src="https://tex.z-dn.net/?f=%20%20%5Cpi%20" id="TexFormula1" title=" \pi " alt=" \pi " a

Allisa [31]

What we know:
shape is circular
Area=64π yr²
Area=πr²
circumference=2πr

In order to find circumference we need r=radius. We can use the area to find r by solving for r using substitution of the information we know above.

Area=πr²
64π=πr² substitution
64π/π=π/πr² multiplicative inverse
64=r²
√64=√r² properties of radicals
8=r We would get two solutions, a positive and negative one but we will only use the positive solution since radius is positive

Circumference=2πr
C=2π(8)=16π yards

7 0

3 years ago

Read 2 more answers

Which expression is equivalent to (3−2^2) 5 ? 5−3^2 5−2^2 2^2−5 3^2−5

tamaranim1 [39]

Well (3-2^2)5 = -5
and 5-3^2=-4
5-2^2=1
2^2-5=-1
3^2-5=4
but if you have to multiply them by 5 as well then (2^2-5)5=-5

8 0

3 years ago

The following picture is a square pyramid where DE=8 cm and m∠ADE=60°.

Goryan [66]

Given:

The length of DE is 8 cm and the measure of ∠ADE is 60°.