Answer:
1). 0.903547
2). 0.275617
Step-by-step explanation:
It is given :
K people in a party with the following :
i). k = 5 with the probability of 
ii). k = 10 with the probability of 
iii). k = 10 with the probability 
So the probability of at least two person out of the 'n' born people in same month is = 1 - P (none of the n born in the same month)
= 1 - P (choosing the n different months out of 365 days) = 
1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)
= 
= 
= 0.903547
2).P( k = 10|at least 2 share their birthday in same month)
=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)
= 
= 0.0.275617
THIS IS EASY. I don't have a calculator on me so bare with me.
1.) 7x - 9 = -4x + 90
7x +9. = -4x. + 9
7x. = -4x. 99
+4x = +4x. + 99
11× = 99
÷ 11. ÷ 11
X = 9
U can solve the rest. Are you serious?
Sequence 1,5,9,13,...
A(0) = 1 +4x0=1
A(1) =1 + 4x1 = 5
A(2) = 1+ 4x2= 9
A(3) = 1 +4x3=13
A(n)= 1+4n A(n-1) = 1+4(n-1) =1+4n-4= - 3+4n
A(n) - A(n-1) = (1+4n) - (-3=4n) = 4
A(n) = A(n-1) +4; 29 is the answer
Answer:
you didnt provide any info over the question
infinitely many solutuinsAnswer:
Step-by-step explanation: