Question

7x-5=8(x*3) what value of x makes this equation true

Answer 1

The given equation is:

$\displaystyle 7x-5=8(x+3)$

The first step you need to do is open the parentheses and distribute the 8 to x+3. It will be 8 times x and 3 times x.

$8(x+3)=8 \times x+ 8 \times 3\\\\8 \times x=8x\\8 \times 3=24$

$8(x+3) \rightarrow 8x+24$

Rewrite the equation:

$7x-5=8x+24$

Now you need to move one of the variables to the other side.

If you move 7x to the other side, then:

You can move the variable by doing the opposite of it. Since 7x is positive, you can move it by subtracting 7x, which is negative. Subtract 7x on both sides:

$7x-5-7x=8x+24-7x\\-5=x+24$

Now you need to leave x alone. x is being added to 24, so remove it by subtracting both sides by 24. Remember that when you're subtracting from a negative number, you're actually adding while keeping the negative sign.

$-5-24=x+24-24$

Subtract:

$\bf-29=x$

If you move 8x to the other side, then:

8x is positive, so you can move it by subtracting 8x, which is negative. Subtract 8x on both sides:

$7x-5-8x=8x+24-8x\\-x-5=24$

You need to leave the variable alone, so move -5 to the other side. You can do this by adding 5 to both sides.

$-x-5+5=24+5\\-x=29$

Lastly, x is negative, but you're looking for the value of positive x. Divide both sides by -1 to remove the negative sign.

$\displaystyle \frac{-x}{-1} =\frac{29}{-1}$

Remember that a positive number divided by a negative number is negative. Divide:

$\bf x=-29$

The answer to your question is x = -29.

Answer 2

Step-by-step explanation:

Question:-

Solve for x

$\\ \tt{:}\leadsto 7x-5=8(x+3)$

SOLUTION:-

$\\ \tt{:}\leadsto 7x-5=8(x+3)$

$\\ \tt{:}\leadsto 7x-5=8x+24$

$\\ \tt{:}\leadsto 7x-8x=24+5$

$\\ \tt{:}\leadsto -x=29$

$\\ \tt{:}\leadsto x=29$